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                  Loop 
                  Return retval。ToString() 
              End Function 
              。 。 。 
          End Class 
          ■Note  In the downloadable source code; the individual steps taken to clean up the data stream are demon
          strated。 For reference; the intermediate development steps in the source code are called Process01()  
          through  Process05()。 
               Let’s review how this code fixes the five problems we discovered。 
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                                                        CH A PT E R   1 0   ■    L E A R N I N G   A B O U T  P E R S IS T E N CE 267 
Empty Lines of Text 
The following code removes the empty lines of text。  
        If splitUpText(0)。Length = 0 Then 
            Continue Do 
        End If 
     When  lotto。txt was processed; the output data stream generated a single field array for  
an empty line。 So; we know that if the first field element has a length of zero; the line of text  
should be ignored。 
Empty Fields and Too Many Fields 
The next problem in our list is that some lines have empty text fields at the end。 Solving this  
problem would probably entail a solution similar to the previous one; but you should think of  
the big picture and understand that solving one problem might also solve another problem。 In  
this case; solving the problem of the empty fields also helps solve the problem of having too  
many fields。 
     Both of these problems are solved by knowing the data that is being manipulated。 As you’ve  
seen; the data stream assumes the following format: date; then lottery numbers 1 to 6; and then  
the bonus number。 The parts of the data stream that are not correct have the same format; with  
some extra information like replay number and empty fields。 Thus; the fix is to copy the date  
and append the remaining fields; as follows: 
            retval。Append(newDate) 
            For c1 As Integer = 0 To 7  
                retval。Append(〃 〃 & splitUpText(c1)) 
            Next 
     The first line of code appends the date to the StringBuilder buffer (retval)。 Then in the  
For loop that follows; a space and the fields 0 to 7 are copied to the StringBuilder buffer。 
Incorrect Data Format 
In some of the fields; the date has a period separator; in others; it has a hyphen。 The correct  
format is a period; and the code that fixes the date format is as follows: 
        If splitUpText(0)。Contains(〃…〃) Then 
            Dim dateSplit As String() = splitUpText(0)。Split(New Char() {〃…〃c}) 
            Dim newDate As String = 
                dateSplit(0) & 〃。〃 & dateSplit(1) & 〃。〃 & dateSplit(2) 
     A fix is needed if the first field contains a hyphen。 The  If statement tests for this using the  
Contains() method。 If a fix is needed; the first field is separated again into three subfields; where  
each subfield represents a part of the date (year; month; day)。 Then those three subfields are  
rebined and separated using the period and assigned to the variable newDate。 
Duplicate Dates 
The last problem that needs to be solved is having duplicate dates in the data stream。 The  
following code fixes this problem (the duplicate date code is bolded)。 
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268       CH AP T E R   1 0   ■    L E A R N I N G   A B OU T   P E R S IS TE N CE 
                      If _dates。Contains(splitUpText(0)) Then 
                          Continue Do 
                      End If 
                      If splitUpText(0)。Length = 0 Then 
                          Continue Do 
                      End If 
                      If splitUpText(0)。Contains(〃…〃) Then 
                          Dim dateSplit As String() = splitUpText(0)。Split(New Char() {〃…〃c}) 
                          Dim newDate As String = _ 
                              dateSplit(0) & 〃。〃 & dateSplit(1) & 〃。〃 & dateSplit(2) 
                          If _dates。Contains(newDate) Then 
                              Continue Do 
                          End If 
                          _dates。Add(newDate) 
                          retval。Append(newDate) 
                          For c1 As Integer = 0 To 7 
                              retval。Append(〃 〃 & splitUpText(c1)) 
                          Next 
                      Else 
                          _dates。Add(splitUpText(0)) 
                          retval。Append(lineOfText) 
                      End If 
               Of all the problems we needed to solve; this is the trickiest; because it required multiple  
          pieces of code in multiple places。 The code processes the data stream and keeps a list of dates。  
          A date is added to the list only if the date does not exist in the list; which is checked using the  
          Contains() method。 The  lists expose this method to verify if the object being passed to it  
          equals one of the list members。 The way that most lists implement the method is to iterate each  
          method and call the Equals() method。 The catch is that if you declare a custom type; the  Equals()  
          method defaults to verifying if one reference value equals another。 You would need to imple
          ment a custom  Equals() method。  
          ■Note  When you encounter situations where you need to write multiple pieces of code in multiple places;  
          that is a sign that you are about to create code that is hard to maintain。 You should take a close look at the  
          code; and If possible; rewrite it。 Of course; this depends on a lot of factors。 So sometimes; you will need to  
          just write the code; test it; and hope that it works。 
               With the final solution; the console application TextProcessor is plete。 You could  
          process lotto。txt and get a correctly formatted data stream。