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VB2008从入门到精通(PDF格式英文版)-第127章

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                  Loop 

                  Return retval。ToString() 

              End Function 

              。 。 。 

          End Class 



          ■Note  In the downloadable source code; the individual steps taken to clean up the data stream are demon

          strated。 For reference; the intermediate development steps in the source code are called Process01()  

          through  Process05()。 



               Let’s review how this code fixes the five problems we discovered。 


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                                                        CH A PT E R   1 0   ■    L E A R N I N G   A B O U T  P E R S IS T E N CE 267 



Empty Lines of Text 



The following code removes the empty lines of text。  



        If splitUpText(0)。Length = 0 Then 

            Continue Do 

        End If 



     When  lotto。txt was processed; the output data stream generated a single field array for  

an empty line。 So; we know that if the first field element has a length of zero; the line of text  

should be ignored。 



Empty Fields and Too Many Fields 



The next problem in our list is that some lines have empty text fields at the end。 Solving this  

problem would probably entail a solution similar to the previous one; but you should think of  

the big picture and understand that solving one problem might also solve another problem。 In  

this case; solving the problem of the empty fields also helps solve the problem of having too  

many fields。 

     Both of these problems are solved by knowing the data that is being manipulated。 As you’ve  

seen; the data stream assumes the following format: date; then lottery numbers 1 to 6; and then  

the bonus number。 The parts of the data stream that are not correct have the same format; with  

some extra information like replay number and empty fields。 Thus; the fix is to copy the date  

and append the remaining fields; as follows: 



            retval。Append(newDate) 

            For c1 As Integer = 0 To 7  

                retval。Append(〃 〃 & splitUpText(c1)) 

            Next 



     The first line of code appends the date to the StringBuilder buffer (retval)。 Then in the  

For loop that follows; a space and the fields 0 to 7 are copied to the StringBuilder buffer。 



Incorrect Data Format 



In some of the fields; the date has a period separator; in others; it has a hyphen。 The correct  

format is a period; and the code that fixes the date format is as follows: 



        If splitUpText(0)。Contains(〃…〃) Then 

            Dim dateSplit As String() = splitUpText(0)。Split(New Char() {〃…〃c}) 

            Dim newDate As String = 

                dateSplit(0) & 〃。〃 & dateSplit(1) & 〃。〃 & dateSplit(2) 



     A fix is needed if the first field contains a hyphen。 The  If statement tests for this using the  

Contains() method。 If a fix is needed; the first field is separated again into three subfields; where  

each subfield represents a part of the date (year; month; day)。 Then those three subfields are  

rebined and separated using the period and assigned to the variable newDate。 



Duplicate Dates 



The last problem that needs to be solved is having duplicate dates in the data stream。 The  

following code fixes this problem (the duplicate date code is bolded)。 


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268       CH AP T E R   1 0   ■    L E A R N I N G   A B OU T   P E R S IS TE N CE 



                      If _dates。Contains(splitUpText(0)) Then 

                          Continue Do 

                      End If 

                      If splitUpText(0)。Length = 0 Then 

                          Continue Do 

                      End If 

                      If splitUpText(0)。Contains(〃…〃) Then 

                          Dim dateSplit As String() = splitUpText(0)。Split(New Char() {〃…〃c}) 

                          Dim newDate As String = _ 

                              dateSplit(0) & 〃。〃 & dateSplit(1) & 〃。〃 & dateSplit(2) 

                          If _dates。Contains(newDate) Then 

                              Continue Do 

                          End If 

                          _dates。Add(newDate) 

                          retval。Append(newDate) 

                          For c1 As Integer = 0 To 7 

                              retval。Append(〃 〃 & splitUpText(c1)) 

                          Next 

                      Else 

                          _dates。Add(splitUpText(0)) 

                          retval。Append(lineOfText) 

                      End If 



               Of all the problems we needed to solve; this is the trickiest; because it required multiple  

          pieces of code in multiple places。 The code processes the data stream and keeps a list of dates。  

          A date is added to the list only if the date does not exist in the list; which is checked using the  

          Contains() method。 The  lists expose this method to verify if the object being passed to it  

          equals one of the list members。 The way that most lists implement the method is to iterate each  

          method and call the Equals() method。 The catch is that if you declare a custom type; the  Equals()  

          method defaults to verifying if one reference value equals another。 You would need to imple

          ment a custom  Equals() method。  



          ■Note  When you encounter situations where you need to write multiple pieces of code in multiple places;  

          that is a sign that you are about to create code that is hard to maintain。 You should take a close look at the  

          code; and If possible; rewrite it。 Of course; this depends on a lot of factors。 So sometimes; you will need to  

          just write the code; test it; and hope that it works。 



               With the final solution; the console application TextProcessor is plete。 You could  

          process lotto。txt and get a correctly formatted data stream。
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